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Home/ Questions/Q 7602677
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Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T23:28:22+00:00 2026-05-30T23:28:22+00:00

So I have a table that holds references to other tables like: local a

  • 0

So I have a table that holds references to other tables like:

local a = newObject()
a.collection = {}
for i = 1, 100 do
    local b = newObject()
    a[#a + 1] = b
end 

Now if I want to see if a particular object is within “a” I have to use pairs like so:

local z = a.collection[ 99 ]
for i,j in pairs( a.collection ) do
    if j == z then
    return true
  end
end

The z object is in the 99th spot and I would have to wait for pairs to iterate all the way throughout the other 98 objects. This set up is making my program crawl. Is there a way to make some sort of key that isn’t a string or a table to table comparison that is a one liner? Like:

if a.collection[{z}] then return true end

Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T23:28:23+00:00Added an answer on May 30, 2026 at 11:28 pm

    Why are you storing the object in the value slot and not the key slot of the table?

    local a = newObject()
    a.collection = {}
    for i = 1, 100 do
        local b = newObject()
        a.collection[b] = i
    end 
    

    to see if a particular object is within “a”

    return a.collection[b]
    

    If you need integer indexed access to the collection, store it both ways:

    local a = newObject()
    a.collection = {}
    for i = 1, 100 do
        local b = newObject()
        a.collection[i] = b
        a.collection[b] = i
    end 
    

    Finding:

    local z = a.collection[99]
    if a.collection[z] then return true end
    
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