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Home/ Questions/Q 6850465
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T01:07:40+00:00 2026-05-27T01:07:40+00:00

So I have an array of arrays which contain only strings. The array of

  • 0

So I have an array of arrays which contain only strings.
The array of arrays is to be displayed as a table and may have over 1000 rows with 20 or more values in each.

eg:

var arr = [
    ["bob","12","yes"],
    ["joe","","no"],
    ["tim","19","no"],
    ["dan","","yes"],
    ["tim","",""],
    ["dan","0",""]
]

the strings may contain anything that can be represented as a string, including: " ", "", "0" or "00-00-00" etc… and any column my be used for ordering.

I am sorting the arrays ascending and descending but some of the values I am sorting by are blank strings: "". How could I get the blank strings (only) to always be at the end of the new arrays in all modern browsers?

currently they are at the end when ascending but at the start when descending.

I am sorting like below (Yes I’m sure I can do it shorter too):

if (direction == "asc") {
    SortedArr = arr.sort(function (a, b) {
        if (a[colToSortBy] == '') {
            return -1;
        }
        if (a[colToSortBy].toUpperCase() < b[colToSortBy].toUpperCase()) {
            return -1;
        }
        if (a[colToSortBy].toUpperCase() > b[colToSortBy].toUpperCase()) {
            return 1;
        }
        return 0;
    });
} else {
    SortedArr = arr.sort(function (a, b) {
        if (a[colToSortBy] == '') {
            return -1;
        }
        if (b[colToSortBy].toUpperCase() < a[colToSortBy].toUpperCase()) {
            return -1;
        }
        if (b[colToSortBy].toUpperCase() > a[colToSortBy].toUpperCase()) {
            return 1;
        }
        return 0;
    });
}
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  1. Editorial Team
    Editorial Team
    2026-05-27T01:07:41+00:00Added an answer on May 27, 2026 at 1:07 am

    Empty strings at the end

    Working example on JSFiddle that puts empty strings always at the end no matter whether order is ascending or descending. This may be a usability issue, but this is the solution:

    if (direction == "asc") {
        SortedArr = arr.sort(function (a, b) {
            return (a[col] || "|||").toUpperCase().localeCompare((b[col] || "|||").toUpperCase())
        });
    } else {
        SortedArr = arr.sort(function (a, b) {
            return (b[col] || "!!!").toUpperCase().localeCompare((a[col] || "!!!").toUpperCase())
        });
    }
    
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