Question

So I have an if statement in PHP that looks like this:

if ($_GET['Squares'] != 0)

but really I need to check if the variable squares has been passed via the url. So it needs to be if squares doesn’t exist. I tried the following but it throws errors.

if (!isset $_GET['Squares'])

Can anyone tell me what the correct syntax is please?

Answer 1

Add parentheses around the isset() call:

if (!isset($_GET['Squares']))

In PHP, all function calls have to have parentheses around the arguments. Be sure not to confuse language constructs as functions, such as print and echo which can be called without parenthesis.