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Home/ Questions/Q 1051963
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T17:01:02+00:00 2026-05-16T17:01:02+00:00

So i have such code. public interface IGeoDataSet<out T> : IDataSet where T :

  • 0

So i have such code.

public interface IGeoDataSet<out T> : IDataSet
    where T : IGeoPrimitive<IGeoPrimitiveContent>
{
    IEnumerable<T> Items { get; } 
}

public interface IDataSet { }

public interface IGeoPrimitive<T> : IPrimitive
    where T : IGeoPrimitiveContent
{
    T Content { get; }
}

public interface IPrimitive { }

public interface IGeoPrimitiveContent { }

And such inplementation for previous interfaces.

public class TriangleDataSet : IGeoDataSet<Triangle>
{
    public IEnumerable<Triangle> Items { get; private set; }
}

public class Triangle : IGeoPrimitive<TriangleContent>
{
    public TriangleContent Content { get; private set; }
}

public class TriangleContent : IGeoPrimitiveContent { }

When I try to compile this code I’ve got an error:

The type '.Triangle' cannot be used as type parameter 'T' in the generic type or method '.IGeoDataSet<T>'. There is no implicit reference conversion from '.Triangle' to '.IGeoPrimitive<.IGeoPrimitiveContent>'.

I can’t understand why, maybe someone knows what is the problem?

Br,
Jevgenij

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T17:01:03+00:00Added an answer on May 16, 2026 at 5:01 pm

    You need for your IGeoPrimitive<T> interface to also be covariant in order to be able to use Triangle as the type parameter for a IGeoDataSet<out T> implementation:

    // Note addition of 'out' keyword
    public interface IGeoPrimitive<out T> : IPrimitive
        where T : IGeoPrimitiveContent
    {
        T Content { get; }
    }
    

    This is because you have a where T : IGeoPrimitive<IGeoPrimitiveContent> constraint; but without IGeoPrimitive<T> being covariant, a Triangle (which implements IGeoPrimitive<TriangleContent>) does not meet this constraint.

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