Question

So I have the directory struture like this

  Execute_directory--> execute.py
  |
  Algorithm ---> algorithm.py
            |
            |--> data.txt

So I am inside execute directory and have included the following path to my python path.

sys.path.append(os.path.dirname(os.path.abspath(__file__)) + "/../Algorithm")

algorithm.py has a code to read data.txt

So when I run execute.py , execute.py calls algorithm.py which in turns read data.txt
I thought that above line should have done the job. it is able to find algorithm.py but not data.txt??

         IOError: [Errno 2] No such file or directory:'data.txt'

Any clue what I am doing wrong ??
Thanks

Answer 1

Are you reading data.txt in algorithm.py like this:

open('data.txt')

Because that is relative to the working directory and not relative to the scripts directory.

In algorithm.py you could try this:

open(os.path.join(os.path.dirname(__file__), 'data.txt'))