Question

So i have the following code:

<?php
$users_id = $_POST['users_id'];
    if ($users_id=="1");
    {
    ?>
        <td><select name="User">
        <option></option>
        <option>John</option>
        <option>Jack</option>
        </select></td>  
<?php
    }
    if ($users_id!=="1");
    {
    ?>      
        <td align="left"> <input type="text" name="User" /><br></td></tr>
<?php
    }
    ?>

I want only one form to be shown (dropdown or input), but i always get both of them and
I can’t figure it out what is wrong with my if statement.
Please help!
Thank you for your time and effort!

Answer 1

Remove your code and paste this one…
it will surely work

<?php
$user_id = (isset($_POST['users_id'])) ? $_POST['users_id'] : '';
if($user_id == 1){
?>
<td><select name="User">
<option></option>
<option>John</option>
<option>Jack</option>
</select></td>
<?php
} else {
?>
<td align="left"> <input type="text" name="User" /><br></td>
<?php
}
?>
</tr>

Changes made in your code
done validation of post field,
removed ; from if condition,
used if-else instead of if-if,
placed </tr> after all processing, else it will return an visible error