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Home/ Questions/Q 1114847
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T03:04:07+00:00 2026-05-17T03:04:07+00:00

So I have this array of pointers image* [] myArray; And I copy the

  • 0

So I have this array of pointers

image* [] myArray;

And I copy the objects in the array into a new, larger array.

for (int i=0; i<maxObjects; i++){
  newArray[i] = myImages[i];
}
for (int i=maxObjects; i<newMaxObjects; i++){
  newArray[i] = NULL;
}

The point of this is to resize my array. Then I delete myArray:

delete [] myArray;

Which, I presume deletes the objects from the array, as well as the pointer to those objects. Now I want to declare myArray again

image* [] myArray;

and set this to point to my new, larger array.

myArray = newArray;

This is where I get lost: now I’ve got two pointers to the same array. myArray points to the same thing as newArray, right? Or, am i wrong, and myArray now points to newArray (the pointer), which points to the object I want?

My main questions: How do I delete the temporary pointer myArray without deleting the data it points to? Also, how do I assign the myArray pointer directly to the data, rather than pointing to another pointer? Am I doing it right or is there a better way to do what I’m doing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T03:04:07+00:00Added an answer on May 17, 2026 at 3:04 am
    • This is where I get lost: now I’ve
      got two pointers to the same array.
      myArray points to the same thing as
      newArray, right? Or, am i wrong, and
      myArray now points to newArray (the
      pointer), which points to the object
      I want?

    myArray is assigned the same value as newArray, which is the memory location of the first element of newArray. After you say myArray = newArray; , if you assign newArray to NULL, myArray will still point to the datapointers.

    • My main questions: How do I delete
      the temporary pointer myArray without deleting the data it points to?

    myArray = NULL; Will just reset the pointer. delete [] myArray; will deallocate the memory you saved for the pointers that point to your data, but WILL NOT delete the actual data.

    • Also, how do I assign the myArray
      pointer directly to the data,
      rather than pointing to another
      pointer? Am I doing it right or is
      there a better way to do what I’m
      doing?-

    Using the indirection operator (*) on a pointer which retrieves the data it points to. newerArray will contain an array of pointers to data. newestArray is an array of the data.

    image* newerArray = new (image*)[size];
    for (int i = 0; i < size; i++)
    {
        newerArray[i] = *(myArray[i]);
    }
    
    
    
    image newestArray = new image[size];
    for (int i = 0; i < size; i++)
    {
        newestArray[i] = *(*(myArray[i]));
    }
    
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