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Home/ Questions/Q 6783799
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:54:51+00:00 2026-05-26T16:54:51+00:00

So I have this builder that runs a buildClass method which should be public,

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So I have this builder that runs a buildClass method which should be public, and it takes a couple of arguments.

In my test I want to remove those arguments completely and add something completely different using the Mock in PHPUnit.

So: from:

class ClassBuilder{
  public function buildClass($id, $some, $vars){
    $class = new Class($id, $some, $vars);
    return self::getClass(db_Class, $class);
  }
}

So you might get my idea here, I want to make a mock so it does the return function there.

$myClassStub->getMock("ClassBuilder");
$myClassStub->->expects($this->any())
    ->method("buildClass")
    ->with($this->anything(), $this->anything())
    ->will($this->returnCallback("getClass"));

But I have no idea how it works. This is how I thought it would be, but I have no clue where to put the arguments at all. Please help me out here, much appriciated.

/Marcus

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:54:52+00:00Added an answer on May 26, 2026 at 4:54 pm

    You can just leave out the ->with($this->anything(), $this->anything()) exepct if it is there to make sure that you pass at least 2 arguments into that function.

    Apart from you that I’ve understood is that you want to return a different class. In that case I’d suggest doing:

    $yourClassToReturn = "..."; // create the class here
    
    $myClassStub->getMock("ClassBuilder");
    $myClassStub->expects($this->any())
        ->method("buildClass")
        ->with($this->anything(), $this->anything())
        ->will($this->returnValue($yourClassToReturn));
    
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