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Home/ Questions/Q 9226889
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T04:56:11+00:00 2026-06-18T04:56:11+00:00

So, I have this constructor set up with some prototypes methods and because I

  • 0

So, I have this constructor set up with some prototypes methods and because I need the behavior (that this object creates ) to apply to a few diff. elements, I was wondering if there is a better way than doing the following.

var MAINFUNC = function(opts){
 this.options = {
      item1  : 'somevalue'
  },
  this.init(opts);
}

MAINFUNC.prototype = {
   someFunc1: function(){
       // do stuff
    },
   someFunc2: function(){
       // do stuff
    },
   someFunc3: function(){
         // do stuff
   },
init: function(data){
      $.extend(this.options, data);
      this.someFunc1();
     }
 };
var obj1Create =  new MAINFUNC({ someoptions });
var obj2Create = new MAINFUNC({ someoptions });
var obj2Create = new MAINFUNC({ someoptions });

So, its the last three obj instantiations that seem a tad bit obtuse. Perhaps I am incorrect, but I am thinking there is a more refined way of doing this. And yes, each of thos obj*Create does represent a diff element which needs the behavior that is supplied by MAINFUNC.

Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T04:56:12+00:00Added an answer on June 18, 2026 at 4:56 am
    var MAINFUNC = function(opts)
    {
       var m = Object.create(MAINFUNC.prototype);
       m.options = { ... };
       m.init(opts);
       return m;
    };
    
    var o = [{someoptions}, {someoptions}, {someoptions}].map(MAINFUNC);
    // objects are all now in array
    

    A side benefit of this approach is it makes MAINFUNC work whether you use new or not. This makes it much more manageable, especially with collection functions.

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