Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 174985
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T13:37:10+00:00 2026-05-11T13:37:10+00:00

So, I have two threads. Thread one manages the client connections. (There is only

  • 0

So, I have two threads.

Thread one manages the client connections. (There is only one client and one server)
I call it my server thread.

Thread two manages sending messages to the client. I call it my message processor thread.

Thread one is responsible, among other things sending a heartbeat to the client periodically.

When programming I made an assumption that the sockets weren’t thread safe, but the buffers were, and as long as I was using seperate buffers for the server and processor threads I would be fine.

I also made the assumption that the ‘PrintWriter’ was analogous to the socket buffer in Java.

Under these assumptions I wrote this function to send a heartbeat:

public void sendHeartBeat(){         logger.info('Sending a hearbeat!');         PrintWriter printWriter=null;         try {             printWriter = new PrintWriter(clientSocket.getOutputStream());         } catch (IOException e) {             logger.info(e.toString());         }         if(printWriter!=null){             printWriter.print('HEARTBEAT#');             printWriter.flush();         }     } 

The other thread, the ‘processor’ one does something similar in that it does:

printWriter=new PrintWriter(theServer.getClientSocket().getOutputStream()); 

In this manner I would create a new ‘buffer’ every time I wished to send a heartbeat, and my messages would never get overwritten.

Unfortuneately this does not seem to be the case. And I get an message coming through the pipe like this: dsgdsbHEARTBEAT#sdg

This causes a core dump later.

Here are my questions:

1) Sockets are obviously not thread safe, but are the PrintWriters I get from them thread safe? Or is it just returning the same PrintWriter?

2) What is analogous to the socket buffer in Java? How should I think about this problem?

3) How do I make it so that these threads do not write to the same buffer on the socket?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T13:37:11+00:00Added an answer on May 11, 2026 at 1:37 pm

    It’s a poor design to have these multiple PrintWriters on the same stream. Really you want at least the object the calls them to be synchronised (or thread confined).

    However, assuming for some reason you do want multiple PrintWriters:

    First problem: Writers do not use this as the lock. PrintWriter and BufferedWriter by default both use the Writer they are constructed with as the lock. This is obviously completely broken. They should be using the Writer‘s lock, not the Writer itself. An easy mistake given that having locking a feature of Object removes static type safety. So you’ll need to construct a PrintWriter with the socket OutputStream (or some other common object) as the lock.

    Secondly, we have buffering within PrintWriter. So come the end of a buffer, half get written and half wait for the next write. To prevent that, either externally lock to combine a print and flush, or use auto-flushing and add a new line character.

    So, it isn’t meaningfully thread-safe, but you can hack it. Or you can use a better design.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 207k
  • Answers 207k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer your should try turn the error_reporting to E_ALL i.e. error_reporting(E_ALL);… May 12, 2026 at 9:22 pm
  • Editorial Team
    Editorial Team added an answer You can only use the first form for statically linked… May 12, 2026 at 9:22 pm
  • Editorial Team
    Editorial Team added an answer It needs to be done somewhere where the Response is… May 12, 2026 at 9:22 pm

Related Questions

In socket programming, you create a listening socket and then for each client that
I have an EJB3 application which consists of some EJB's for accessing a DB,
I am looking for a decent programmatic approach to delivering the illusion of riding
Our product contains a task-manager system that allows applications to run code in a

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.