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Home/ Questions/Q 8005585
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T17:16:15+00:00 2026-06-04T17:16:15+00:00

So I know variable && runTrue(); really means if(variable){ runTrue(); } Then is there

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So I know

variable && runTrue();

really means

if(variable){
    runTrue();
}

Then is there a more simplified way to write

if(variable){
    runTrue();
}else{
    runFalse();
}

instead of if-else?

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  1. Editorial Team
    Editorial Team
    2026-06-04T17:16:16+00:00Added an answer on June 4, 2026 at 5:16 pm

    Yes, I found out that this would do the same thing as a normal if-else:

    (variable) && (runTrue(),1) || runFalse();
    

    It is 2 characters shorter (still better than nothing) and tested in jsPerf that usually Short-circut evaluation - false for most of time is faster than the normal way of doing this.

    (variable) &&           //If variable is true, then execute runTrue and return 1
    (runTrue(),1) ||        // (so that it wouldn't execute runFalse)
    runFalse();             //If variable is false, then runFalse will be executed.
    

    But of course, you can always use variable?runTrue():runFalse();.

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