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Home/ Questions/Q 6372665
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:16:01+00:00 2026-05-25T01:16:01+00:00

So I made this function and it works: var opacity = 9; function func()

  • 0

So I made this function and it works:

var opacity = 9;

function func() {
    $("action").style.opacity = "0." + opacity;
    opacity--;

    if (opacity == -1) { window.clearInterval(fading); }
}

var fading = window.setInterval("func()", 200);

But thats acutally not really one single function.
So I did this:

function fadeOut(ms) {
    var opacity = 9;

    function func() {
        $("action").style.opacity = "0." + opacity;
        opacity--;

        if (opacity == -1) { window.clearInterval(fading); }
    }

    var fading = window.setInterval("func()", ms);
}

fadeOut(200);

And suddenly func() is undefined.
Help ? 😐

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:16:01+00:00Added an answer on May 25, 2026 at 1:16 am

    Change:

    var fading = window.setInterval("func()", ms); 
    

    to

    var fading = window.setInterval(func, ms); 
    

    Am not sure what $("action") return though, if its jQuery then style is not a valid member of $(“action”).

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