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Home/ Questions/Q 7547805
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T09:32:48+00:00 2026-05-30T09:32:48+00:00

So I need to build an application that will receive xml request and based

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So I need to build an application that will receive xml request and based on that I will have to return the response xml. I know how to send requests and receive the response, but I have never done it the other way. I would send the request like so:

private function sendRequest($requestXML)
{
    $server = 'http://www.something.com/myapp';
    $headers = array(
    "Content-type: text/xml"
    ,"Content-length: ".strlen($requestXML)
    ,"Connection: close"
    );

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_URL, $server);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_TIMEOUT, 100);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $requestXML);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    $data = curl_exec($ch);



    if(curl_errno($ch)){
        print curl_error($ch);
        echo "  something went wrong..... try later";
    }else{
        curl_close($ch);
    }

    return $data;

}

My question is – what would be the code on the receiving side? How do I catch the incoming request?
Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-30T09:32:50+00:00Added an answer on May 30, 2026 at 9:32 am

    The general idea is to read in the POST value, parse it as XML, make a business decision on it, build out an XML response according to the API you’ve decided on, and write it into the response.

    Read in the POST value:

    $dataPOST = trim(file_get_contents('php://input'));
    

    Parse as XML:

    $xmlData = simplexml_load_string($dataPOST);
    

    Then, you would build out an XML string (or document tree, if you wish), and print it out to the response. print() or echo() will do fine.

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