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Editorial Team
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Asked: 2026-06-01T01:38:50+00:00

so I obtained a piece of html code from a PHP site that returns

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so I obtained a piece of html code from a PHP site that returns the following:

<span class="inline-icon link-icon with-fav" style="background: url("/system/files/imagecache/s_favicon/attachments/links/favicons-201203/1d5920f4b44b27a802bd77c4f0536f5a_48.png?1332860368") no-repeat scroll 0% 0% transparent;"></span>

and then I appended it to a page using javascript 

$('.container').append(variableContainingTheStringAbove);

but then the icon does not display properly and when I inspected element using firebug, the thing instead displays like this: 

<span class="inline-icon link-icon with-fav" transparent;"="" 0%="" scroll="" no-repeat="" 1d5920f4b44b27a802bd77c4f0536f5a_48.png?1332860368")="" favicons-201203="" links="" attachments="" s_favicon="" imagecache="" files="" system="" style="background: url("></span>

what could have possibly gone wrong

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1 Answer

  1. Editorial Team

    Easily spotted once syntax coloring is applied — you need to use single quotes in your inline style instead of nested double-quotes. 

    <span class="inline-icon link-icon with-fav" style="background: url('/system/files/imagecache/s_favicon/attachments/links/favicons-201203/1d5920f4b44b27a802bd77c4f0536f5a_48.png?1332860368') no-repeat scroll 0% 0% transparent;"></span>

    Better yet, use an external class instead of inline styles at all.

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