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Home/ Questions/Q 7409507
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T06:05:35+00:00 2026-05-29T06:05:35+00:00

so i tried to parse the form object with js and pass stuff that

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so i tried to “parse” the form object with js and pass stuff that was supposed to be used to URL and submit a form with ajax.the code did not work.both A and B parameters were not successfully passed to server and response as i thought at the first place.

<html>
<head>
<script type="text/javascript">
function ajaxForm(form){
 form = document.getElementById(form);
 var elements = form.elements;
 var content="";
 var element;
 for(i=0;i<elements.length;i++){
  element = elements[i];
  if(element.type=="text"){
     content += encodeURIComponent(element.name)+"="+encodeURIComponent(element.value)+"&";
     }
  }
  ajaxSubmit(content);
 }
function ajaxSubmit(content){
    if(content.length==0){
    document.getElementById("txtinput").innerHTML="";
}
if(windows.XMLHttpRequest){
    xmlhttp = new XMLHttpRequest();
}
else{
    xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function(){
    if(xmlhttp.readyState == 4 && xmlhttp.status == 200){
        document.getElementById("txtinput").innerHTML=xmlhttp.responseText;
    }
}
xmlhttp.open("GET","process.php?"+content,true);
xmlhttp.send();
}
</script>
</head>

<body>
<form id="ajax_form">
 A:<input type="text" name="A" />
<br/>
 B:<input type="text" name="B" />
<input type="submit" onsubmit="ajaxForm('ajax_form')" />
</form>
<p>Elevator:<span id="txtinput" ></span><br/></p>
</body>
</html>

process.php:

<?php 
 $response = "This is simply an example for debugging purposes";
 echo $response;
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T06:05:35+00:00Added an answer on May 29, 2026 at 6:05 am

    AjaxForm and AjaxSubmit are never getting called, instead the form is getting submitted in the normal way. You need something like

    <form id="ajax_form" onsubmit="ajaxForm('ajax_form');return false;">
    
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