Question

So I want to do something like this sql code below:

select s.id, s.name,s.city 
from stuff s
group by s.name having count(where city and name are identical) > 1

To produce the following, (but ignore where only name or only city match, it has to be on both columns):

id      name  city   
904834  jim   London  
904835  jim   London  
90145   Fred  Paris   
90132   Fred  Paris
90133   Fred  Paris

Answer 1

Duplicated id for pairs name and city:

select s.id, t.* 
from [stuff] s
join (
    select name, city, count(*) as qty
    from [stuff]
    group by name, city
    having count(*) > 1
) t on s.name = t.name and s.city = t.city