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Home/ Questions/Q 3333080
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T23:45:26+00:00 2026-05-17T23:45:26+00:00

So, I want to match the following link structures with a preg_match_all in php..

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So, I want to match the following link structures with a preg_match_all in php..

<a garbage href="http://this.is.a.link.com/?query=this has invalid spaces" possible garbage>
<a garbage href='http://this.is.a.link.com/?query=this also has has invalid spaces' possible garbage>
<a garbage href=http://this.is.a.link.com/?query=no_spaces_but_no_delimiters possible garbage>
<a garbage href=http://this.is.a.link.com/?query=no_spaces_but_no_delimiters>

I can get ” and ‘ deilmited urls one by doing

'#<a[^>]*?href=("|\')(.*?)("|\')#is'

or I can get all 3, but not if there are spaces in the first two with:

'#<a[^>]*?href=("|\')?(.*?)[\s\"\'>]#is'

How can I formulate this so that it will pick up ” and ‘ delimited with potential spaces, but also properly encoded URLs without delimiters.

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  1. Editorial Team
    Editorial Team
    2026-05-17T23:45:26+00:00Added an answer on May 17, 2026 at 11:45 pm

    OK, this seems to work:

    '#<a[^>]*?href=((["\'][^\'"]+["\'])|([^"\'\s>]+))#is'
    

    ($matches[1] contains the urls)

    Only annoyance is that quoted urls have the quotes still on, so you’ll have to strip them off:

    $first = substr($match, 0, 1);
    if($first == '"' || $first == "'")
        $match = substr($match, 1, -1);
    
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