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Home/ Questions/Q 266115
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:49:41+00:00 2026-05-11T22:49:41+00:00

So I wanted to create a toggle-button for a table, where I can make

  • 0

So I wanted to create a toggle-button for a table, where I can make an async call to update a database record (enable/disable).

img

After some trial and error, I have managed to get it working – but it feels like there must be a more elegant way.

  • I don’t like repeating my image-tag in my controller, obviously… How can I avoid that in an elegant way?
  • Is there an overall better way to approach this that what I have done?

Here is my code in the controller:

public ActionResult ToggleEnabled(int id)
    {
        if (Request.IsAjaxRequest())
        {
            var p = this.PageRepository.GetPage(id);
            p.Enabled = p.Enabled != true;
            this.PageRepository.Edit(p);
            return p.Enabled ? Content("<img src='/Content/icons/tick.png' border=0  />") : Content("<img src='/Content/icons/tick_grey.png' border=0  />");
        }
        return Content("Error");
    }

And the view…:

<% var img = Model.Enabled ? "tick.png" : "tick_grey.png"; %>
<% foreach (var item in Model)
       { %>
...
<td align="center">
    <%=Ajax.ActionLink("[replacethis]", 
        "ToggleEnabled", 
                new { id = Model.ID }, 
                new AjaxOptions { UpdateTargetId = "toggleimage" + Model.ID }).Replace("[replacethis]",
                string.Format("<div id='toggleimage{0}'><img src='/Content/icons/{1}' border='0' alt='toggle'/></div>", 
                Model.ID, Model.Enabled ? "tick.png" : "tick_grey.png"))%>
</td>
...
<% } %>

The trick/hack with the Ajax.Actionlink using an image was found here.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:49:42+00:00Added an answer on May 11, 2026 at 10:49 pm

    How about rendering checkbox based on whether the model is enabled or not.

    In jQuery, you can replace those checkboxes with your images. Something like

    Your document.ready code may look like,

    $(document).ready(
    function()
    {
        $('.enabledCheckbox').each(
            function()
            {
                var image = $(this).checked ? 'tick.png' ? 'tick_grey.png';
                $(this).parent.click(
                    function()
                    {
                        if($(this).is('image'))
                            toggleEnabledStatus(); //write code in toggleEnabledStatus to toggle the state of the model on server side.
                    }     
                    );
                $(this).parent.html('<img src=' + image + '/>');
            }
        );
    }
    );
    

    Alternatively, you can use plugin like jquery-checkbox to give them any fancy styling you may think of.

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