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Home/ Questions/Q 8901421
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:21:01+00:00 2026-06-15T01:21:01+00:00

So I was developing an app in Django and needed a function from the

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So I was developing an app in Django and needed a function from the 1.4 version so I decided to update.
But then a weird error appeared when I wanted to do syncdb
I am using the new manage.py and as You can see it makes some of the tables but then fails :

./manage.py syncdb
Creating tables ...
Creating table auth_permission
Creating table auth_group_permissions
Creating table auth_group
Creating table auth_user_user_permissions
Creating table auth_user_groups
Creating table auth_user
Creating table django_content_type
Creating table django_session
Creating table django_site
Traceback (most recent call last):
  File "./manage.py", line 9, in <module>
    execute_from_command_line(sys.argv)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/__init__.py", line 443, in execute_from_command_line
    utility.execute()
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/__init__.py", line 382, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 196, in run_from_argv
self.execute(*args, **options.__dict__)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 232, in execute
    output = self.handle(*args, **options)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/base.py", line 371, in handle
    return self.handle_noargs(**options)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/core/management/commands/syncdb.py", line 91, in handle_noargs
    sql, references = connection.creation.sql_create_model(model, self.style,     seen_models)
  File "/usr/local/lib/python2.7/dist-packages/Django-1.4-py2.7.egg/django/db/backends/creation.py", line 44, in sql_create_model
    col_type = f.db_type(connection=self.connection)
TypeError: db_type() got an unexpected keyword argument 'connection'
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  1. Editorial Team
    Editorial Team
    2026-06-15T01:21:03+00:00Added an answer on June 15, 2026 at 1:21 am

    I had the same issue, the definition for my custom field was missing the connection parameter.

    from django.db import models
    
    class BigIntegerField(models.IntegerField):
        def db_type(self, connection):
            return "bigint"
    
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