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Home/ Questions/Q 3876322
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T22:22:07+00:00 2026-05-19T22:22:07+00:00

So I wrote up this little peace of code as practice for myself… But

  • 0

So I wrote up this little peace of code as practice for myself…

But i am getting in travers_inorder function at line *traverse_inorder(p->left)* memory access violation and program crashes.
Why???
Any ideas?

UPDATE: I am using visual studio 2008 SP1 an visual C++ compiler

#include <iostream>
#include <time.h>

using namespace std;

struct tree_node
{
tree_node *left;
tree_node *right;
int value;
};
void populate_rnd_tree(tree_node *root, int cnt);
void traverse_inorder(tree_node *p);

int main()
{
srand(time(NULL));
tree_node * nTmp = new tree_node;

populate_rnd_tree(nTmp, 10);

traverse_inorder(nTmp);

return 1;
}

void populate_rnd_tree(tree_node *root, int cnt)
{
tree_node *old = root, *left, *right;

left = new tree_node;
right = new tree_node;

int val = 0;
// exit condition
if (cnt == 0) return;

val = rand()%50;
old->value = val;
old->left = left;
old->right = right;

populate_rnd_tree(left, cnt-1);
populate_rnd_tree(right, cnt-1);

return;
}

void traverse_inorder(tree_node *p)
{ 
if (p != NULL)
{
    traverse_inorder(p->left);
    cout << p->value << endl;
    traverse_inorder(p->right);
}
} 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T22:22:07+00:00Added an answer on May 19, 2026 at 10:22 pm

    My best guess: looks like you never actually set your final child nodes to NULL in your tree generation procedure. As such, your conditional to stop traversing is never hit, as left and right are just uninitialized pointers. In populate_rand_tree, do the following:

    if (cnt == 0) 
    {
        old->left = NULL;
        old->right = NULL; 
        return;
    }
    

    Alternatively, since you are using C++…

    struct tree_node
    {
        tree_node() : left(NULL), right(NULL) { }
    
        tree_node *left;
        tree_node *right;
        int val;
    }
    
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