Question

So if I have a table as follows

with column

date       datetime
employee   varchar

and I want to find all the records where a particular user has the same date more than once

and for each duplicate found I would need

date    employee    numDuplicates

Answer 1

You can use GROUP BY with HAVING clause:

SELECT employee, [date], Count(*) As numDuplicates
FROM Table
GROUP BY employee, [date]
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC