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Asked: 2026-06-13T10:25:50+00:00

So I’m attempting to grab text from a file when it appears in double

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So I’m attempting to grab text from a file when it appears in double quotations, EXCEPT when the text within the quotations ends in a certain suffix.

For example below, I’d want everything NOT ending in VER that is in quotations to be parsed.

Example Input:

"GameVER": ["GM435615-IQR", "LG-QR435", "HG145-IR9", "WUT828-PQR10"] "VERIZON": ["GKSL42375834-45", "DG-67498", "GF4564", "HFJ-88.8.98"]

Output:

GM435615-IQR
LG-QR435
HG145-IR9WUT828-PQR10
VERIZON
GKSL42375834-45
DG-67498
GF4564
HFJ-88.8.98

In python, I’ve tried this:

re.findall(r'(\"\b.+?)(?!VER)\b\"',text)

But it still grabs the words with VER on the end.

Any help would be apperciated.

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1 Answer

  1. Editorial Team

    It’s because the VER is being caught in the .+? (the ? makes the .+ non-greedy but in this case the only way for a ....VER to be caught is by having it in the .+?). Instead of saying “match stuff not followed by ‘VER'”, try “match a word where the last 3 characters are not VER” (i.e. an end quote not preceded by ‘VER’).

    Also, instead of using .+ try [^"] which will avoid your .+ matching across multiple words.

    re.findall(r'\"(\b[^"]+)(?<!VER)\b\"',text)

    example:

    >>> text='"GameVER": ["GM435615-IQR", "LG-QR435", "HG145-IR9", "WUT828-PQR10"] "VERIZON": ["GKSL42375834-45", "DG-67498", "GF4564", "HFJ-88.8.98"]'
>>> re.findall(r'\"(\b[^"]+)(?<!VER)\b\"',text)
['GM435615-IQR', 'LG-QR435', 'HG145-IR9', 'WUT828-PQR10', 'VERIZON', 'GKSL42375834-45', 'DG-67498', 'GF4564', 'HFJ-88.8.98']

    (by the way in your output above you missed out “HG145-IR9” and “WUT828-PQR10” although they do not end in VER and are in double quotes?)

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