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Home/ Questions/Q 5931381
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:41:11+00:00 2026-05-22T14:41:11+00:00

So, I’m digesting a protein sequence with an enzyme (for your curiosity, Asp-N) which

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So, I’m digesting a protein sequence with an enzyme (for your curiosity, Asp-N) which cleaves before the proteins coded by B or D in a single-letter coded sequence. My actual analysis uses String#scan for the captures. I’m trying to figure out why the following regular expression doesn’t digest it correctly…

(\w*?)(?=[BD])|(.*\b)

where the antecedent (.*\b) exists to capture the end of the sequence.
For:

MTMDKPSQYDKIEAELQDICNDVLELLDSKGDYFRYLSEVASGDN

This should give something like: [MTM, DKPSQY, DKIEAELQ, DICN, DVLELL, DSKG, ... ] but instead misses each D in the sequence.

I’ve been using http://www.rubular.com for troubleshooting, which runs on 1.8.7 although I’ve also tested this REGEX on 1.9.2 to no avail. It is my understanding that zero-width lookahead assertions are supported in both versions of ruby. What am I doing wrong with my regex?

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:41:12+00:00Added an answer on May 22, 2026 at 2:41 pm

    The simplest way to support this is to split on the zero-width lookahead:

    s = "MTMDKPSQYDKIEAELQDICNDVLELLDSKG"
    p s.split /(?=[BD])/
    #=> ["MTM", "DKPSQY", "DKIEAELQ", "DICN", "DVLELL", "DSKG"]
    

    For understanding as to what was going wrong with your solution, let’s look first at your regex versus one that works:

    p s.scan(/.*?(?=[BD]|$)/)
    #=> ["MTM", "", "KPSQY", "", "KIEAELQ", "", "ICN", "", "VLELL", "", "SKG", ""]
    
    p s.scan(/.+?(?=[BD]|$)/)
    #=> ["MTM", "DKPSQY", "DKIEAELQ", "DICN", "DVLELL", "DSKG"]
    

    The problem is that if you can capture zero characters and still match your zero-width lookahead, you succeed without advancing the scanning pointer. Let’s look at a simpler-but-similar test case:

    s = "abcd"
    p s.scan //      # Match any position, without advancing
    #=> ["", "", "", "", ""]
    
    p s.scan /(?=.)/ # Anywhere that is followed by a character, without advancing
    #=> ["", "", "", ""]
    

    A naive implementation of String#scan might get stuck in an infinite loop, repeatedly matching with the pointer before the first character. It appears that once a match occurs without advancing the pointer the algorithm forcibly advances the pointer by one character. This explains the results in your case:

    1. First it matches all the characters up to a B or D,
    2. then it matches the zero-width position right before the B or D, without moving the character pointer,
    3. as a result the algorithm moves the pointer past the B or D, and continues on after that.
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