Question

So I’m doing what the title says with this code

else if(input[0] == 'i'){
        printf("This works");
        if(isspace(input[1])){
            x = 2;
            while(input[x] != '\0'){
                tempS[x - 2] = input[x];
            }
            inp = atoi(tempS);
            for(x = x-2; x >= 0; x--){
                tempS[x] == NULL;
            }
            insert(&linkedList, inp);
            printf("%i %s %c", inp, " sucessfully inserted.", '\n');
        }
    }

You can ignore the insert, basically I get user input which should be i and some number.

For example: i 27

Then the program should recognize that it’s i in that else if, and take the number after the i.

Variable initialization is as follows.

char *input;
int inp = 0;
int x = 0;
char *tempS[255];

Thanks in advance.

Edit: The problem is that I get a segmentation fault before even the printf.

Answer 1

You are stuck in an infinite loop.

 while(input[x] != '\0')
 {
          tempS[x - 2] = input[x];
 }

Add the instruction x++; So you can read the next element in the array input, otherwise, you are stuck in the position x = 2.

This char *input; it is only a pointer, you have to allocate memory to use it like you are currently using. Do the following:

input = malloc(sizeof(char) * N);

N is the number of elements that you want to have in the input array.

You are getting segmentation fault because you are trying to access memory, which was not allocated before.