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Home/ Questions/Q 8497109
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T00:02:12+00:00 2026-06-11T00:02:12+00:00

So I’m finally starting learn efficient programming (Used to use one class for everything),

  • 0

So I’m finally starting learn efficient programming (Used to use one class for everything), and this new game I’m making has the following classes so far:

  • GameDriver
  • Map
  • Block
  • Player

And as of right now, Map creates an ArrayList of Block objects, and the GameDriver creates a Map object and a Player object, now that’s all working perfectly fine and good. But now I ran into a problem.

I added a method to Player called checkLand() and GameDriver calls that method to check if the player can step on a certain spot, but for the method to be able to check it, it needs access to the map object that the GameDriver is using so I tried this:

public class Player(){
    GameDriver gameDriver = new GameDriver();
    ...more declarations    

    public boolean checkLand(int xCord, int yCord){
        if (gameDriver.map.world.get(gameDriver.map.getByCords(xCord,yCord)).type == 1) {
            return false;
        } else {
            return true;
        } 

    }

But obviously it doesn’t work, but I wanted to show you guys so you could get an understanding of what I want it to do, should I just have the checkLand method in GameDriver? I want to know the best way please 🙂

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  1. Editorial Team
    Editorial Team
    2026-06-11T00:02:14+00:00Added an answer on June 11, 2026 at 12:02 am

    Since the Player object is being created by the GameDriver object, you should be able to access the Player object within your GameDriver class. Also, you said that the Map object is also being created within your GameDriver class, so that is also available.

    What you could do would be to have a method in your Player class which takes a Map object as parameter and does the logic you need.

    This will allow your GameDriver object to call an object which it has (Player) and pass it another object it also has (Map).

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