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Home/ Questions/Q 7794523
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T22:48:07+00:00 2026-06-01T22:48:07+00:00

So I’m looking to take input such as 7:00 AM as a start time,

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So I’m looking to take input such as 7:00 AM as a start time, and say, 10:00 PM as an endtime, and then compare a set of times (also in the form of 8:00 AM, 3:00 PM, etc) to see if those time are or aren’t in the range of time. Is there a good way to create a “day” that has a range of hours (the endtimes can be as late as 4:00 AM, so I was figuring I would go from 6:00 AM – 5:59 AM instead of midnight – 11:59 PM, if that’s possible) that I can check times against?

For example: starttime = 8:00 AM, endtime = 3:00 AM, and checking time = 7:00 AM would return time as being out of the range.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-01T22:48:08+00:00Added an answer on June 1, 2026 at 10:48 pm

    Use datetime parsing and comparison capabilities:

    from datetime import datetime, timedelta
    
    def parse_time(s):
        ''' Parse 12-hours format '''
        return datetime.strptime(s, '%I:%M %p')
    
    starttime = parse_time('8:00 AM')
    endtime   = parse_time('3:00 AM')
    if endtime < starttime:
       # add 1 day to the end so that it's after start
       endtime += timedelta(days=1)
    
    checked_time = parse_time('7:00 AM')
    
    # Can compare:
    print starttime <= checked_time < endtime
    
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