Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7561871
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T13:16:15+00:00 2026-05-30T13:16:15+00:00

So I’m looping through a set of JSON arrays, and then looping through each

  • 0

So I’m looping through a set of JSON arrays, and then looping through each individual array.

If I remove the two if statements it will loop through both data sets and append the ‘target’ with both ‘data’ sets, but like it is now, it will only append the items.join through the first each loop.

The case stuff was an if loop first, thinking it would matter, but no.

Strange thing is, the consoleOut (like console.log) does print my stuff, so It actually does loop through both arrays within the JSON set.

    $.each(data, function(keys, vals)
    {

    var items = [];


     $.each(data[keys], function(key, val) 
     {

        var currString = JSON.stringify(val);
        switch (key)
        {
        case "ID":              
            consoleOut("ID: "+currString+" loaded");
        break;                                      

        case "parentIDs":

            consoleOut("parentIDs: "+currString);
        break;
        case "UID":
            consoleOut("UID: "+currString);
            UID = unquote(currString);
        break;
        case "title":
            consoleOut("Title: "+currString);
            items.push('<H1 class="' + key + '">' + unquote(currString) + '</H1>');
        break;
        case "img":
            consoleOut("IMG: "+currString);

            if ($(currString).val() !== '')
            {
            items.push('<IMG class="' + key + '" src='+currString+'></IMG>');               
            };
        break;
        case "text":
            consoleOut("TXT: "+currString);

            if ($(currString).val() !== '')
            {
            items.push('<P class="' + key + '">'+currString+'</P>');

            };
        break;
        }
      });
      consoleOut("---------");

      $('<DIV/>', {
        'id': UID,
        html: items.join('')
      }).appendTo(target);
    } 
) 

I’m wondering how the if statements are breaking my appending to the main ‘items’ array..

(When I don’t stringify the val at the beginning it will loop, but that’s because the if statements are then true, but stop working when false.. So maybe It’s better to modify my if statement for that, but I’m still puzzled as to how the .push stops working?)

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-30T13:16:17+00:00Added an answer on May 30, 2026 at 1:16 pm
    $(currString).val() 
    

    It is saying you are making an element and looking at the value attribute of that element. Is that what you really want? I do not think image or text has a value.

    I would think you would want to use length or html()

    [EDIT] Looking at your object, you just want to check the lenght of currString

    if( currString && currString.length>0 ) {
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to loop through a bunch of documents I have to put
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Basically, what I'm trying to create is a page of div tags, each has
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I need a function that will clean a strings' special characters. I do NOT
I have an array which has BIG numbers and small numbers in it. I
I've tracked down a weird MySQL problem to the two different ways I was
I have a .ini file as follows: [playlist] numberofentries=2 File1=http://87.230.82.17:80 Title1=(#1 - 365/1400) Example
I have a jquery bug and I've been looking for hours now, I can't

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.