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Home/ Questions/Q 512093
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:17:04+00:00 2026-05-13T07:17:04+00:00

So I’m reading http://learnyouahaskell.com/starting-out as it explains lists, and using ghci on Vista 64.

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So I’m reading http://learnyouahaskell.com/starting-out as it explains lists, and using ghci on Vista 64. It says that [2,4..20] steps by 2 from 4 to 20. This works. It says [20,19..1] goes from 20 to 1, but doesn’t explain. I take it that the first number is NOT the step, the step is the difference between the 1st and 2nd number. This is confirmed by [4,4..20] which hangs (no error message, must kill console). This is unlike operators like !! and take which check the index’s range and give an error message.

My question is: is this a bug on Vista port or is that the way it’s supposed to be?

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:17:05+00:00Added an answer on May 13, 2026 at 7:17 am

    [x,y..z] does indeed step from x to z by step y-x. When y-x is 0 this leads to an infinite list. This is intended behavior.

    Note that if you use the list in an expression like take 20 [2,2..20], ghci won’t try to print the whole list (which is impossible with infinite lists of course) and it won’t “hang”.

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