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Home/ Questions/Q 9222821
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:55:35+00:00 2026-06-18T03:55:35+00:00

So im trying to create a dynamic image gallery. And each image created would

  • 0

So im trying to create a dynamic image gallery. And each image created would have a div on top for users to click on. Im unable to bind a click event to the div

The Code

$(document).ready(function()
{
    if()
    {

    }
    else
    {
        var divImgContainer =  '<div id="imgContainer">';
        var divInfo         = '<div id="info">';
        var divDetails      = '<div id="details">';
        var divImage        = '<div id="image">';
        var divVote         = '<div id ="click">';
        for(i=0; i<$ImageArray.length; i++)
        {
             document.getElementById("container").innerHTML += divImgContainer+divInfo+divDetails+'Caption</div>'+divVote+'</div></div>'+divImage+'<a href="img/'+$ImageArray[i].link +'"><img src="'+$ImageArray[i].thumb+'" /></a></div></div>';
         }
        $('#click').click(function()
        {
            alert("click");
        });
    }
});

Googling gave two popular answers one is $('#click').click(function() and the other is $('#click').live(click,function() both of which does not work.

Is there any specific way to bind click events for dynamically generated div?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T03:55:36+00:00Added an answer on June 18, 2026 at 3:55 am

    first of all, do not create multiple divs with the same IDs

    assuming element id ‘click’ has class ‘vote’ and that you want to click on any div with the class ‘vote’, try this:

    $('#container').on('click', '.vote', function(e){
        alert("click");
    });
    
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