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Home/ Questions/Q 1023747
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:40:28+00:00 2026-05-16T11:40:28+00:00

So, I’m trying to have same data plotted based on a drop down filter,

  • 0

So, I’m trying to have same data plotted based on a drop down filter, but I haven’t gotten past the storing the data to the variable passing to the plotting function. my alert gives object Object, but shouldn’t it be totalValue (for this example)?

the html

   <select id="performance_chart_filter">
  <option value="totalValue">Total by Value</option>
  <option value="openValue">Open by Value</option>
  <option value="declinedValue">Declined by Value</option>
  <option value="acceptedValue">Accepted by Value</option>
</select>

the javascript

$j("#performance_chart_filter").change(function(){
    plotWithChoice();
});



function plotWithChoice() {
   var d = {
        "totalValue": {
            label: "Total",
            clickable: true,
            hoverable: true,
            data: <%= @total %>
        }
.
.
.
};

    var filter = $j("#performance_chart_filter");
    var data = [d[filter.val()]];
alert(data);
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  1. Editorial Team
    Editorial Team
    2026-05-16T11:40:28+00:00Added an answer on May 16, 2026 at 11:40 am

    No. filter.val() would most likely be the string "totalValue".

    d[filter.val()] (or d["totalValue"]) would be the value of the property totalValue of the object d, which is an object thus the output Object object of the alert, because that’s the default string representation of a generic object like this.

    And [d[filter.val()]] is a Array with one element namely the object mentioned above.

    To debug this, I’d suggest you use a Debugger (such as Firebug), because that can display objects in a readable form.

    Or use the .toSource() method:

    alert(data.toSource());
    
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