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Home/ Questions/Q 8389093
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:37:48+00:00 2026-06-09T18:37:48+00:00

So I’m trying to use jQuery’s deferred (and the fact that $.ajax returns a

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So I’m trying to use jQuery’s deferred (and the fact that $.ajax returns a promise) to handle some asynchronous code.

Here’s a quick example which shows what’s happening

var update_model = function(model, resp){
    model.set('id', resp.id);
    m = model;
};

var print_id = function(){
    console.log(m.get('id'));
};

var MyModel = Backbone.Model.extend({});
var m = new MyModel({title: 'test'});

var model_promise = m.save({author: 'me'}, {success: update_model});

$.when(model_promise).then(print_id);

The problem is that print_id is being called BEFORE update_model and I’m not sure how to make it happen the other way around.

In the actual example, I’m trying to save anywhere from 1 to 100 models, and I need to get the IDs from those models before I can move onto the next step.

Am I missing something basic here?


EDIT

update_model does get called — it just happens after print_id. Also, I’ve tried using the done method on model_promise and then using then:

model_promise.done(update_model).then(print_id);

But then update_model doesn’t receive it’s necessary arguments.

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:37:50+00:00Added an answer on June 9, 2026 at 6:37 pm

    The problem is that your deferred resolves in the success method. To use deferreds w/the ajax methods use the the deferred.done().then() pattern (check out the “The jqXHR Object” section here: http://api.jquery.com/jQuery.ajax/).

    var update_model = function(model, resp){ 
      model.set('id', resp.id); 
      m = model; 
    };
    
    var print_id = function(){ 
      console.log(m.get('id')); 
    };
    
    var MyModel = Backbone.Model.extend({}); 
    var m = new MyModel({title: 'test'});
    
    var $model_promise = m.save({author: 'me'});
    
    $model_promise.done(update_model).then(print_id);
    
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