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Home/ Questions/Q 6737707
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T11:16:51+00:00 2026-05-26T11:16:51+00:00

So I’m working on a Perl script that does a large amount of processing

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So I’m working on a Perl script that does a large amount of processing (nothing too complicated, but lots of it) and decided to do a little benchmark to compare two common methods of trimming strings.

The first method is a quick one-liner:

$word =~ s/^\s+|\s+$//g;

The second method is a little longer, but does the same thing:

$word =~ s/^\s+//;
$word =~ s/\s+$//;

For my benchmarks, I had the script read from a file with 40 million lines, trimming each (does nothing other than that). The average line length is under 20 bytes.

The first method took on average 87 seconds to complete.
The second method took on average 27 seconds to complete.
Doing no processing (just read line, continue) takes an average 16 seconds.

The first method (first pass) will match either all the leading or trailing whitespace, then remove it, then match and remove the leading/trailing whitespace on the other side.
The second method matches and removes all leading whitespace, then matches and removes all trailing whitespace.

Maybe I’m in the wrong here, but why would the second method be over 3x faster than the first?

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  1. Editorial Team
    Editorial Team
    2026-05-26T11:16:52+00:00Added an answer on May 26, 2026 at 11:16 am

    It makes a sense that anchored non-backtracking patterns can be optimized WAY better (effectively a single forward/backward sequential scan starting from a known character position);

    Chances are that the ‘option’ (|) makes the optimizer back off and you get standard backtracking, quite badly so, because many spaces might occur that are not trailing

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