Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7489293
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 29, 20262026-05-29T15:13:36+00:00 2026-05-29T15:13:36+00:00

So I’m working on an SQL problem, in which I have a bars and

  • 0

So I’m working on an SQL problem, in which I have a bars and beer database from which I want to:
list all bars which serve a beer that Mike likes, and which are frequented by more than one drinker.

The database consists of:

likes (drinker, beer)
frequents(dinker, bar)
sells(bar, beer)

So I tried:

SELECT bar
FROM beer.sells
WHERE beer IN 
(SELECT beer
FROM beer.likes
WHERE drinker = 'Mike') AND bar IN
(SELECT bar FROM beer.frequents HAVING COUNT(drinker) > 1)

Which didn’t work… why doesn’t the count(drinker) comparison work as a filter to filter out bars that have less than 2 drinkers who frequent them?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-29T15:13:36+00:00Added an answer on May 29, 2026 at 3:13 pm

    Looks like you need a GROUP BY bar in the bar subquery. Otherwise, you’ll effectively get COUNT(*) from beer.frequents, which isn’t what you want:

    SELECT bar
    FROM beer.sells
    WHERE beer IN 
    (SELECT beer
    FROM beer.likes
    WHERE drinker = 'Mike') AND bar IN
    (SELECT bar FROM beer.frequents GROUP BY bar HAVING COUNT(drinker) >= 2)
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a text area in my form which accepts all possible characters from
I have a French site that I want to parse, but am running into
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I am currently running into a problem where an element is coming back from
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I have a reasonable size flat file database of text documents mostly saved in
I'm working with an upstream system that sometimes sends me text destined for HTML/XML
I have a bunch of posts stored in text files formatted in yaml/textile (from
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.