Question

So I’m working with django and file uploads and I need a javascript function to execute after the file has been uploaded.
I have a file upload handler in my views.py which looks like this:

def upload_file(request):   
    form = UploadFileForm(request.POST, request.FILES)
    if form.is_valid():        
        for f in request.FILES.getlist('fileAttachments'):     
            handle_uploaded_file(f)
        return HttpJavascriptResponse('parent.Response_OK();')
    else:
        return HttpResponse("Failed to upload attachment.")

And I found a django snippet from http://djangosnippets.org/snippets/341/ and I put the HttpJavascriptResponse class in my views.py code. It looks as follows:

class HttpJavascriptResponse(HttpResponse):
    def __init__(self,content):
       HttpResponse.__init__(self,content,mimetype="text/javascript")

However, when I upload a file the browser simple renders “parent.Response_OK();” on the screen instead of actually executing the javascript. And Chrome gives me the warning: “Resource interpreted as Document but transferred with MIME type text/javascript”

Is there anyway to get views.py to execute the script?

Answer 1

I believe this will work.

return HttpResponse("<script>parent.Response_OK();</script>")

However, you might think about returning a success (200) status code in this case, and then having some javascript in parent attach to the load event of this child, and branch based on return status code. That way you have a separation of view rendering code and view behavior code.