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Home/ Questions/Q 6207943
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:43:17+00:00 2026-05-24T05:43:17+00:00

So in my implementation file, i have NSString *post = [NSString stringWithFormat:@json=%@,jsonString]; NSData *postData

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So in my implementation file, i have

NSString *post = [NSString stringWithFormat:@"json=%@",jsonString];
NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:NO];
NSMutableData *postMutData = [[NSMutableData alloc] initWithData:postData];
ASIFormDataRequest *asi_request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:urlString]];
[asi_request setDidFinishSelector:@selector(gotMyInfo:)];
[asi_request setPostBody:postMutData];
[asi_request setDelegate:self];
[asi_request startAsynchronous];

and in my php, i have

$json = $_POST['json'];
$info = json_decode($json);

but i get an error: Undefined index ‘json’
it’s odd because i check the post with

$input = file_get_contents('php://input');
echo $input;

and it shows the json={….} properly.
I know i can just use the $input and decode the json from there but it seems “ugly”. Does anybody know why $_POST isn’t working for this??

Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:43:20+00:00Added an answer on May 24, 2026 at 5:43 am

    Wow i figured out the problem.. I used the setPostBody:postMutData which doesn’t send form data to the php, so php won’t recognize it with $_POST I needed to do

    [asi_request addPostValue:jsonString forKey:@"json"]; 
    

    then it’ll send the ?json={…}

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