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Home/ Questions/Q 1085661
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:43:00+00:00 2026-05-16T22:43:00+00:00

So I’ve been doing this for as long as I can remember, but I’m

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So I’ve been doing this for as long as I can remember, but I’m curious if this is really what I should be doing. You write a function that takes a parameter, so you anticipate it to have a value, but if it doesn’t, you have a good reason to default it, to say zero. What I currently do is write a helper function:

function foo() { return foo(0); };
function foo(bar) { ... };

I just ran across an instance where I did this and I looked at it oddly for a few seconds before understanding my logic behind it. I come from php where it’s trivial:

function foo(bar=0) { ... }

Is there a javascript alternative that I’m not aware of?

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:43:01+00:00Added an answer on May 16, 2026 at 10:43 pm

    You can’t have overloaded functions in JavaScript. Instead, use object based initialization, or check for the values and assign a default if none supplied.

    In your example, the second function foo(bar) will replace the first one.

    Here’s a function using object initialization.

    function foo(config) {
        extend(this, config);
    }
    

    where extend is a function that merges the config object with the current object. It is similar to the $.extend method in jQuery, or $extend method of MooTools.

    Invoke the function and pass it named key value pairs

    foo({ bar: 0 });
    

    The other way to initialize is to look at the supplied values, and assign a default if the value is not given

    function foo(bar) {
        bar = bar || 0;
    }
    

    This works as long as bar is not a falsy value. So foo(false) or foo("") will still initialize bar to 0. For such cases, do an explicit check.

    function foo(bar) {
        bar = (typeof bar == 'undefined' ? 0 : bar);
    }
    
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