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Home/ Questions/Q 8644535
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T12:19:03+00:00 2026-06-12T12:19:03+00:00

So I’ve created this jqueryui widget. Its creates a div that I can stream

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So I’ve created this jqueryui widget. Its creates a div that I can stream errors into. The widget code looks like this:

$.widget('ui.miniErrorLog', {
   logStart: "<ul>",   // these next 4 elements are actually a bunch more complicated.
   logEnd:   "</ul>",
   errStart: "<li>",
   errEnd:   "</li>",
   content:  "",
   refs:     [],

   _create: function() { $(this.element).addClass( "ui-state-error" ).hide(); },

   clear: function() { 
      this.content = ""; 
      for ( var i in this.refs )
         $( this.refs[i] ).removeClass( "ui-state-error" );
      this.refs = [];
      $(this.element).empty().hide(); 
   }, 

   addError: function( msg, ref ) {
      this.content += this.errStart + msg + this.errEnd; 
      if ( ref ) {
         if ( ref instanceof Array )
            this.refs.concat( ref );
         else
            this.refs.push( ref );
         for ( var i in this.refs )
            $( this.refs[i] ).addClass( "ui-state-error" );
      }
      $(this.element).html( this.logStart + this.content + this.logEnd ).show();
   }, 

   hasError: function()
   {
      if ( this.refs.length )
         return true;
      return false;
   },
});

I can add error messages into it, and references to page elements that is will put into an error state. I use it to validate dialogs. In the “addError” method I can pass in a single id, or an array of ids, like this:

$( "#registerDialogError" ).miniErrorLog( 
   'addError', 
   "Your passwords don't match.", 
   [ "#registerDialogPassword1", "#registerDialogPassword2" ] );

But when I pass in an array of id’s it doesn’t work. The problem is in the following lines (i think):

if ( ref instanceof Array )
   this.refs.concat( ref );
else
   this.refs.push( ref );

Why doesn’t that concat work. this.refs and ref are both arrays. So why doesn’t the concat work?

Bonus: am I doing anything else dumb in this widget? It’s my first one.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T12:19:04+00:00Added an answer on June 12, 2026 at 12:19 pm

    The concat method doesn’t change the original array, you need to reassign it.

    if ( ref instanceof Array )
       this.refs = this.refs.concat( ref );
    else
       this.refs.push( ref );
    
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