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Home/ Questions/Q 6206703
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:29:45+00:00 2026-05-24T05:29:45+00:00

So I’ve got this URL regex: /(?:((?:[^-/’:!=a-z0-9_@]|^|\:))((https?://)((?:[^\p{P}\p{Lo}\s].-|[^\p{P}\p{Lo}\s])+.[a-z]{2,}(?::[0-9]+)?)(/(?:(?:([a-z0-9!*’;:=+\$/%#[]-_,~]+))|@[a-z0-9!*’;:=+\$/%#[]-_,~]+/|[.\,]?(?:[a-z0-9!*’;:=+\$/%#[]-_~]|,(?!\s)))*[a-z0-9=#/]?)?(\?[a-z0-9!*'();:&=+\$/%#[]-_.,~]*[a-z0-9_&=#/])?))/iux What it’s currently matching: http://www.google.com http://google.com I

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So I’ve got this URL regex:

/(?:((?:[^-/”‘:!=a-z0-9_@]|^|\:))((https?://)((?:[^\p{P}\p{Lo}\s].-|[^\p{P}\p{Lo}\s])+.[a-z]{2,}(?::[0-9]+)?)(/(?:(?:([a-z0-9!*’;:=+\$/%#[]-_,~]+))|@[a-z0-9!*’;:=+\$/%#[]-_,~]+/|[.\,]?(?:[a-z0-9!*’;:=+\$/%#[]-_~]|,(?!\s)))*[a-z0-9=#/]?)?(\?[a-z0-9!*'();:&=+\$/%#[]-_.,~]*[a-z0-9_&=#/])?))/iux

What it’s currently matching:

  • http://www.google.com
  • http://google.com

I need it to also match:

  • http://www.google.com
  • google.com

I tried making the protocol part of the regex optional by slapping a ? at the end “(https?:\/\/)?” but that didn’t do anything.

Ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:29:46+00:00Added an answer on May 24, 2026 at 5:29 am

    I’d look for something in the language that you are using to do this. URLs are tough to match with a regex. If you insist, I changed yours to make the (https?://) optional. I did not check it though.

    /(?:((?:[^-/"':!=a-z0-9_@]|^|\:))((https?://)?((?:[^\p{P}\p{Lo}\s].-|[^\p{P}\p{Lo}\s])+.[a-z]{2,}(?::[0-9]+)?)(/(?:(?:([a-z0-9!*';:=+\$/%#[]-_,~]+))|@[a-z0-9!*';:=+\$/%#[]-_,~]+/|[.\,]?(?:[a-z0-9!*';:=+\$/%#[]-_~]|,(?!\s)))*[a-z0-9=#/]?)?(\?[a-z0-9!*'();:&=+\$/%#[]-_.,~]*[a-z0-9_&=#/])?))/iux
    

    I got this example from the RFC 3986 and was directed there by this comment. Although, I’d still recommend using something from whatever language you are using rather than a regex.

    ^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?
    

    Since you are using PHP, did you consider using parse_url? It looks like it will return false on bad urls.

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