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Home/ Questions/Q 407875
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:38:15+00:00 2026-05-12T17:38:15+00:00

So, let say I have this: var d = document.createElement(‘div’); d.id = whatever;` So,

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So, let say I have this:

var d = document.createElement('div');
d.id = "whatever";`

So, d is the DOM object,

how can I create or convert it into jQuery object?

e.g.
$(d) ???

and, how to ‘read’ all attributes of the jQuery object? just like the var_dump of PHP.

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:38:15+00:00Added an answer on May 12, 2026 at 5:38 pm
    // create a jQuery-boosted div
    $div = $('<div></div>');
    $div.attr('id','someId');
    alert($div.attr('id'));
    
    // to get the DOM element:
    var div = $div[0];
    
    // or
    var div = $div.get(0);
    

    or just wrap the dom element in $() as you suggested:

    $(d).attr('id','someId');
    $(d).blah();
    

    Use attr to get/set element attributes. I’m not sure if there’s a one-liner that can dump all of an element’s attributes and their respective values (firebug serves that purpose for me), but you can create an array with all the attribute names you’re interested in, and do something like:

    var attr = ['name', 'id', 'src', 'foo'];
    var len = attr.length;
    for (var i = 0; i < len; i++) 
        alert($(d).attr(attr[i]));
    

    or using $.each:

    $.each(['name', 'id', 'src', 'foo'], function(i,val) {
        alert( 'Attribute: ' + val + ' Value: ' + $(d).attr(val) );
    });
    
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