Question

So lets say I have this code:

public void bar(){
  synchronized(foo){foo.remove(0)}
}

public void doStuff(){
  synchronized(foo){
     bar()
  }
}

Will synchronized realize that the current chain I’m in has this lock and inherit it or will it deadlock?

Answer 1

The lock you get from a synchronized block is reentrant. This will not dead-lock, a thread can acquire a lock on the same object multiple times.

See Intrinsic Locks and Synchronization.