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Home/ Questions/Q 5848817
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T12:54:46+00:00 2026-05-22T12:54:46+00:00

So long story short I have an object model in which several different entity

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So long story short I have an object model in which several different entity types share a common supertype. Any type derived from this supertype has an owning User associated with it, and I want to provide a generic utility function that can return all the entities of a given type belonging to a specified User.

All of that works fine, but my function declaration looks like:

public static <T> List<T> findByUser(Class<T> entityClass, User user, EntityManager em)

…and although this is accepted by the compiler, the syntax looks a little strange to me. Is this the correct way to declare a function with a generic return type? Ideally what I’d like to have is something more like:

public static List<T> findByUser(Class<T extends MySuperClass> entityClass, User user, EntityManager em)

But the compiler doesn’t like that at all. So my specific questions are:

  1. Is there any way to get rid of the seemingly spurious <T> element after static?
  2. What is the syntax that I need to use to make the compiler enforce that T must be derived from my superclass type?
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  1. Editorial Team
    Editorial Team
    2026-05-22T12:54:47+00:00Added an answer on May 22, 2026 at 12:54 pm
    public static <T extends MySuperClass> List<T> findByUser(Class<T> entityClass, User user, EntityManager em)
    

    should work.

    The <T extends MySuperClass> is needed in the method signature (after static) as that is where the bounds of the type T are being defined.

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