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Home/ Questions/Q 770067
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:26:19+00:00 2026-05-14T18:26:19+00:00

So most of us know how to access an outer class from an inner

  • 0

So most of us know how to access an outer class from an inner class. Searches with those words give oodles of answered questions on that topic. But what I want to know is why the syntax is the way it is.

Example:

public class A
{
    private class B
    {
        public void c()
            {A.this.d();}

        public void d()
            {System.out.println("You called the d() in the B class! Oh noes!");}
    }

    public void d()
        {System.out.println("You've called d()! Go, you!");}
}

Why is it A.this.d()? It looks like this is a static field of class A, but… * am confused *

Forgive me if this is a repeat; like I said, searches with those words give how-answers.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T18:26:19+00:00Added an answer on May 14, 2026 at 6:26 pm

    Why is it done that way? Really, it’s just because of the way it is. It works, it sort of makes sense, and there’s no need to come up with fancy syntax to do the job.

    When you see something like this:

    x.y.z
    

    The . can mean a lot of things:

    • Subpackage separator
    • Member field access
    • Nested type separator

    In other words, the . is overloaded to serve many grammatical functions within Java programming language. It may lead to confusion, and it can be problematic, but that’s just the way it is.

    It helps to follow naming convention, but certain things can still look ambiguous and/or confusing.

    See also

    • Sun Naming Conventions
    • JLS 6.5 Determining the Meaning of a Name
      • This section has many examples showing how names can be resolved
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