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Home/ Questions/Q 9167111
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:18:38+00:00 2026-06-17T15:18:38+00:00

So my joomla site crashes throwing me this error , the weird thing is

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So my joomla site crashes throwing me this error , the weird thing is that the other guy being on my site at the sametime in another state still has my site working for him ok … It crashes when I try to save info to post in the database .. Below is the error, i WOULD appreciate and be forever grateful for any tip to fix this ! Thanks !! By the way , I was browsing it from the starbucks and everyone’s using wifi …

Error loading module MySQL server has gone away SQL=SELECT m.id, m.title, m.module, m.position, m.content, m.showtitle, m.params, mm.menuid FROM pwo3d_modules AS m LEFT JOIN pwo3d_modules_menu AS mm ON mm.moduleid = m.id LEFT JOIN pwo3d_extensions AS e ON e.element = m.module AND e.client_id = m.client_id WHERE m.published = 1 AND e.enabled = 1 AND (m.publish_up = '0000-00-00 00:00:00' OR m.publish_up <= '2013-01-22 04:58:42') AND (m.publish_down = '0000-00-00 00:00:00' OR m.publish_down >= '2013-01-22 04:58:42') AND m.access IN (1,1,2,3) AND m.client_id = 0 AND (mm.menuid = 207 OR mm.menuid <= 0) ORDER BY m.position, m.ordering

Warning: Invalid argument supplied for foreach() in /home/content/72/9959172/html/libraries/joomla/database/database/mysql.php on line 383

Warning: Invalid argument supplied for foreach() in /home/content/72/9959172/html/libraries/joomla/database/database/mysql.php on line 383

Warning: Invalid argument supplied for foreach() in /home/content/72/9959172/html/libraries/joomla/database/table.php on line 406
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  1. Editorial Team
    Editorial Team
    2026-06-17T15:18:40+00:00Added an answer on June 17, 2026 at 3:18 pm
    Warning: Invalid argument supplied for foreach()
    

    You should check that what you are passing to foreach is an array by using the is_array function

    If you are not sure it’s going to be an array you can always check using the following PHP example code:

    if (is_array($variable)) {
    
      foreach ($variable as $item) {
       //do something
      }
    }
    

    This means you have an error in your SQL too since it does not return any data to the foreach as far as I can understand. Make sure that your SQL is correct.

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