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Home/ Questions/Q 8733915
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:44:40+00:00 2026-06-13T09:44:40+00:00

So now I have this method: public static String convert(String str) { if (str.equals(#

  • 0

So now I have this method:

public static String convert(String str) {

    if (str.equals("# "))
    System.out.println(" ");

Pattern pattern = Pattern.compile("(#+[^#]+)");
Matcher matcher = pattern.matcher(str);

while (matcher.find()) {
    String str1 = matcher.group(1);
    int n = str1.length() - str1.replaceFirst("#+", "").length();
System.out.println("<h" + n + ">" + str1.substring(n) + "</h" + n + ">");
}

return ("");
}    

When I type ###Le Monde # it gives me < h3>Le Monde < /h3> < h1> < /h1>. I would like it to ignore the # following “le monde”. Basically, I want the algorithm to ignore a series of # followed by a space or return key. What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:44:41+00:00Added an answer on June 13, 2026 at 9:44 am

    Add another line after getting the next match (str1), so:

    String str1 = matcher.group(1);
    if(str1.replaceFirst("#+", "").length() == 0 || str1.replaceFirst("#+", "").matches("[\\s]+")) continue;
    

    That will ignore any whitespaces matches.

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