Question

So on the command line in linux I am trying to search some HTML code and print just a dynamic part of the code. For example this code

<p><span class="RightSideLinks">Tel: [phone]</span></p>

I would just want to print 97543 not the 090. The next time I search the file the code might have changed to

<p><span class="RightSideLinks">Tel: [phone]</span></p>

And I just want the 82827. The rest of the code stays the same just the phone numbers change.

Can I use grep to do this?
Thanks

Edit:

Would it be possible to use it on this code too?

<tr class="patFuncEntry"><td align="left" class="patFuncMark"><input type="checkbox" name="renew0" id="renew0" value="i1061700" /></td><td align="left" class="patFuncTitle"><label for="renew0"><a href="/record=p1234567~S0"> I just want to print this part. </a></label>

What changes on that is the record number: p1234567~S0" and the text that I want to print.

Answer 1

One way using GNU grep:

grep -oP '(?<=Tel: .{3} )[^<]+' file.txt

Example contents of file.txt:

<p><span class="RightSideLinks">Tel: [phone]</span></p>
<p><span class="RightSideLinks">Tel: [phone]</span></p>

Results:

97543
82827

EDIT:

(?<=Tel: .{3} ) ## This is a positive lookbehind assertion, which to be
                ## interpreted must be used with grep's Perl regexp flag, '-P'.

Tel: .{3}       ## So this is what we're actually checking for; the phrase 'Tel: '
                ## followed by any character exactly three times followed by a 
                ## space. Since we're searching only for numbers you could write
                ## 'Tel: [0-9]{3} ' instead.

[^<]+           ## Grep's '-o' flag enables us to return exactly what we want, 
                ## rather than the whole line. Therefore this expression will
                ## return any character except '<' any number of times.

Putting it all together, we're asking grep to return any character except '<' 
any number of times if we can find 'Tel: .{3} ' immediately ahead of it. HTH.