Question

So quick, odd question:
I took an exam, and a question was:

char c = 'A'
char *p =&c
char **p2 = &p
void *v = &p2

Write the type (i.e. int, void*, etc.) of the following expression:

1. &v
2. p2 + 1
3. v[0]

I answered:

1. void **
2. char**
3. ILLEGAL

and lost full credit. I just wanted to get a second opinion from someone before I try to get points back.

1. I wasn’t too sure about, but I figured that, since v was a void pointer to a memory address, the address of v would have been a void**. If v was dereferenced, however, it would be a char****.

2. p2 is a char**, so adding 1 to it would still make it a char**.

3. v[0] doesn’t exist.

If someone could help me out with this kind of dumb problem, I’d be very grateful.
Thank you.

Answer 1

Your answers are correct, for the reasons you gave (apart for the bit about dereferencing v, although it sounds like you already know that you can’t dereference a void *).