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Home/ Questions/Q 3318178
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:40:29+00:00 2026-05-17T22:40:29+00:00

So right now I have the code $(‘[name=dept]’).live(‘change’,function() { $(‘#course’).load(‘getCla.php?dept=’+$(this).val()); $(‘select.speedC’).selectmenu({style:’dropdown’,maxHeight: 250}); }); Basically,

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So right now I have the code

$('[name=dept]').live('change',function() {
$('#course').load('getCla.php?dept='+$(this).val());
$('select.speedC').selectmenu({style:'dropdown',maxHeight: 250}); 
});

Basically, what it does is propagate a form select menu after a value is chosen. The problem is, the third line doesn’t have its intended action, it it tries to execute before the 2nd line finishes filling the list.

Is there a way to make the 3rd line wait until the list has finished propagating? (As filling the list reformats the list).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:40:30+00:00Added an answer on May 17, 2026 at 10:40 pm

    Use the callback parameter of .load(), like this:

    $('#course').load('getCla.php?dept='+$(this).val(), function() { 
      $('select.speedC').selectmenu({style:'dropdown',maxHeight: 250}); 
    });
    

    The callback runs when the response comes back and the #course element has the new content. It also receives the returned html from the server as the first argument, if you need it for any reason.

    Also since your initial selector is so expensive, I highly recommend .delegate() here, like this:

    $('body').delegate('[name=dept]', 'change', function() {
      $('#course').load('getCla.php?dept='+$(this).val(), function() { 
        $('select.speedC').selectmenu({style:'dropdown',maxHeight: 250}); 
      });
    });
    
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