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Home/ Questions/Q 7986811
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T11:57:36+00:00 2026-06-04T11:57:36+00:00

So suppose I have a number called num , if some condition A happens,

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So suppose I have a number called num, if some condition A happens, then increase the number by 1, else decrease it.

I could write the code like this:

if (A) ++num;
else --num;

This piece of code could also be written without any if-else, but would involve more arithmetics (just simple basic arithmetics, no exponents, logarithms or anything that one would need a scientific calculator to do!)
Something like this:

num = num * x + y;

The question is, would the first or the second block of code perform faster? (This is in Java, btw).

(Please don’t say it wouldn’t make any difference. This is just very ‘rudimentary’ version of what I’m trying to do. But suppose there were an extremely good profiler that could measure the difference in runtime between these two’s, which one would be faster?)

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-04T11:57:38+00:00Added an answer on June 4, 2026 at 11:57 am

    These kind of optimizations doesn’t make much sense and are evil most of the time, especially in the Java virtual machine, that have JIT and that optimize the bytecode.

    Keep the code as more readable as you can, don’t worry about this kind of optimization …

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