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Home/ Questions/Q 827021
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:30:27+00:00 2026-05-15T03:30:27+00:00

So take the following example: Sub CreateRelation() Dim db As Database Dim rel As

  • 0

So take the following example:

Sub CreateRelation()

   Dim db As Database
   Dim rel As Relation
   Dim fld As Field

   Set db = CurrentDb
   Set rel = db.CreateRelation("OrderID", "Orders", "Products")

   'referential integrity
   rel.Attributes = dbRelationUpdateCascade

   'specify the key in the referenced table
   Set fld = rel.CreateField("OrderID")

   fld.ForeignName = "OrderID"

   rel.Fields.Append fld

   db.Relations.Append rel

End Sub

I keep getting the error:

No unique index found for the referenced field of the primary table.

If I include the vba before this sub to create in index on the field, it gives me the error:

Index already exists.

So I am trying to figure this out. If there are not any primary keys set, will that cause this to not work? I am confused by this, but I really really want to figure this out. So orderID is a FOREIGN KEY in the Products Table

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:30:27+00:00Added an answer on May 15, 2026 at 3:30 am

    You can create a relationship manually through the interface, then reverse engineer it. Here is an Immediate Window session where I examined an existing relationship:

    ? currentdb.Relations.Count
     1 
    
    ? currentdb.Relations(0).Name
    parentchild
    
    ? currentdb.Relations(0).Table
    tblParent
    
    ? currentdb.Relations(0).ForeignTable
    tblChild
    
    ? currentdb.Relations(0).Fields.Count
     1 
    
    ? currentdb.Relations(0).Fields(0).Name
    id
    
    ? currentdb.Relations(0).Fields(0).ForeignName
    parent_id
    

    For reference, this is the sub used to create that relationship:

    Public Sub CreateRelationship()
    Dim strSql As String
    strSql = "ALTER TABLE tblChild" & vbNewLine & _
        "ADD CONSTRAINT parentchild" & vbNewLine & _
        "FOREIGN KEY (parent_id) REFERENCES tblParent (id);"
    CurrentProject.Connection.Execute strSql
    End Sub
    

    Don’t bother with the dbRelationUpdateCascade attribute until after you confirm you have sorted out which are the foreign table and key.

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