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Home/ Questions/Q 6691469
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:45:20+00:00 2026-05-26T05:45:20+00:00

So the following code: $product_id = $(this).parent().parent().html(); Produces this: <div class=right> <input value=6 name=quantity

  • 0

So the following code:

$product_id = $(this).parent().parent().html();

Produces this:

<div class="right">
   <input value="6" name="quantity" id="" maxlength="2" type="text">
   <label> Places required</label>
   <p class="btn update">Update</p>
   <input name="product_id" value="2" class="product_id" type="hidden">
   <p class="btn remove">Remove from basket</p>
</div>
<a href="/product//"><img src="http://dummyimage.com/100x100/333/eee" alt="" class="border-thick shadow"></a>
<div class="left">
   <h5>Title</h5>
   <select name="courses_details_id">
      <option value="">Select date/venue...</option>
      <option value="6">10 Oct 2011 - Chicago, USA</option>
      <option value="4">13 Oct 2011 - Hastings</option>
      <option value="2">18 Nov 2011 - Paris, France</option>
   </select>
   <br>
   <p class="price"><span class="small">From</span> £77.88</p>
</div>

And I simply want to get the value for product_id, so this makes sense:

$('#basket li form select[name=courses_details_id]').change( function(){    
    $(this).parent().parent().children("input[name$=product_id]").val();
});

but it returns a value of undefined

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:45:21+00:00Added an answer on May 26, 2026 at 5:45 am

    Can’t you just do

    $(this).find("input[name='product_id']").val();
    
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